(20/3x^2-13x-10)+(12/3x+2)=x/7x-35

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Solution for (20/3x^2-13x-10)+(12/3x+2)=x/7x-35 equation: 



(20/3x^2-13x-10)+(12/3x+2)=x/7x-35

We move all terms to the left:

(20/3x^2-13x-10)+(12/3x+2)-(x/7x-35)=0



Domain of the equation: 3x^2-13x-10)!=0

x∈R





Domain of the equation: 3x+2)!=0

x∈R





Domain of the equation: 7x-35)!=0

x∈R



We get rid of parentheses

20/3x^2-13x+12/3x-x/7x-10+2+35=0

We calculate fractions

We do not support expression: x^4

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